Quick AJAX question

[Quantz]

Hey I just have a quick question about AJAX and PHP include();... I'll give an explanation of what I'm trying to accomplish.

So my game template is setup so I have 2 "layout" pages included everytime a page is loaded. I have a layout_top.php and a layout_bot.php. So in essence it looks something like:

Code: [Select]

include("layout_top.php");

PAGE CONTENT

include("layout_bot.php");

My layout_top.php script contains a nav bar, and a chat. The chat runs through AJAX and is running perfect so far, updating on its own and accepting new messages with ease.

My layout_bot.php script contains details about your character with a couple bar graphs for HP/Energy/etc and then under that is a few details about the game, time/date/etc.

What I am trying to do is get the HP/Energy bars to be automaticly updated through AJAX. But everytime I try to code it, it will not work. I know its not a syntax problem, because I have rewritten it and scanned over it 15 times now.

I guess what my question is, is if I have all my AJAX calls being made in layout_top.php will they be able to update a <DIV> in layout_bot.php? I figure the answer to that is no. So I try to put my AJAX calls to update the HP/Energy bars at the top of layout_bot.php and still it wont work and I'm thinking because the headers have already been called in layout_top.php? I am not sure. If anyone could let me know and maybe give me some insight on how to solve this problem that would be much appreciated.

Cheers

[Quantz]

Nevermind, I had a table in there as well and I took that out and it started working. I guess you can't have a table and a div working with the same bit of text at the same time for AJAX to work? If anyone could clear that up for me that would be great.

Cheers

[Nox]

You surely can have tables, it can be pretty much anything ... AJAX is basicly fetching the stuff you'd see by typing the url in a browser and using show source option into a variable.

It does not even have to HTML, very often a JSON is returned.

That is - what I wrote might not be absolutelly correct in every case as it is possible to determine, whether the request is an AJAX request or a normal one - so the page can return HTML for normal request and JSON for AJAX.